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Originally Posted by
Vasilis
Gentlemen, you are right.
I was trying to figure out a way to quench a piece while trying to achieve same thermal conductivity of that liquid alloy with the piece of steel being quenched, but I forgot that you have to "force" martensite out of austenite. Without martempering, that's a paradox.
I thought that thermal conductivity was a key for that. Only, you have to go beyond that and drop temperature more violently than steel's own thermal conductivity so that "carbon atoms do not have time to diffuse out of the crystal structure in large enough quantities" for the formation of martensite. It sounds so obvious now that it was way too simple to "achieve maximum hardness with close to zero shock on the piece of steel while losing energy" to be true, laws of phisics don't allow it, martempering aside, again. But playing with the rate the temperature drops could help achieving something that again belongs to the category of martempering.
I would encourage you to continue to think about the problem. As often happens, breakthroughs occur because the status quo argues that nothing new is left to be discovered. On the other hand, you want to get shop work done and the methods that are available do have a track record of some success. And sometimes you will run the experiment knowing it's not likely to succeed because you're bored or you just have to pee on the electric fence for yourself.
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My new question; can we achieve maximum hardness with martempering? To my understanding, we can achieve high hardness while the piece of steel suffers the effects of crystalline changes to a lesser degree, so, good hardness, less damaged blades. But can we go above the, say 62 RC with that method? Again, for a simple steel, low alloy and close to 1% carbon (I'm using O2 steel, it's the cheapest available high quality blanks I can locally find. I'm not asking for this steel specifically but generally).
Is it possible to achieve higher hardness than the 60-62? Submerging blades in liquid Nitrogen and other fancy ways to reach subzero temperatures before or between cycles of tempering sounds bothersome for half a degree RC to do them.
(I remember reading an old chemistry book 20 years ago, elementary school probably, 1960-70 university book, where it was written that with ice and enough CaCl2 you can drop the temperature to below 60 degrees C).
I am going to suggest another course of reading. Find the isothermal transformation diagrams about the particular steel (they each have one if they are common steels or the steel supplier should have one for each that they sell) and read, study, then test the variables. Each of these diagrams has large sample size so the numbers are really pretty valid and reliable. The curves shown will give you predictable information about the correct temperatures and times necessary to achieve the hardness value you desire. If that hardness number is not on the diagram, it's probably not possible for that steel, at least under the conditions specified. Example: 1030 (a simple carbon steel) will not achieve greater than Rc45 under normal conditions of heat treatment. That is as-quenched hardness. Tempering it will reduce the max Rc. You could use a Superquench to achieve a harder "skin" but it's not very deep and the parent material is not Rc45. Such quenchants were not tested developing the diagrams. Most of that benefit would be abraded away honing anyway.