Thank you everyone for your input. I finally got my buff/polish put together. Any improvement comments welcome,
also, any critisim [ well not really]
yea OK guess i 'll welcome that too !
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Thank you everyone for your input. I finally got my buff/polish put together. Any improvement comments welcome,
also, any critisim [ well not really]
yea OK guess i 'll welcome that too !
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A very interesting modification, and a cool way to get an extra wheel. IMO the cutout around the 80 grit wheel makes it look like you won't have much room to maneuver, but one would have to try to know.
I love ingenuity at it's best. It looks like it should work fine (does it?) and is modifiable as well. Interesting use of a drill chuck as well!!
Acually it does work, no problem with manuvering because of cutout.
Your on our way now!:)
You will find that drill chuck to be very versatile. You might want to keep an eye out for additional large pulleys so you can slow the speed down even more.:tu
Your buffer set up rocks! I like it.:tu
Charlie
Yes thanks to youQuote:
Originally Posted by spazola
Randy, I'm mathmatically challenged, ths motor pulley is 1-1/2" and the other 2-1/2" , motor speed 3450rpm. How do i figure the 6" wheel speed?Quote:
Originally Posted by randydance062449
Will be at the Mo. meeting Saturday, hope to speak with you and all the others, see ya then.
Quote:
Originally Posted by paco
Hi Steve,
Hope I can answer this without confusing you too much.
Remember in school when we all said "when will I ever use algebra?" This is a time when we will.
The circumference of a circle is (PI) multiplied by the Diameter where PI is aprox. 3.14.
Your drive side runs at 3450 rpm, you multiply this times our circumference which gives us a value for the drive side. You have an unknown RPM and the circumference of the driven pulley. Because the two sides are connected by a belt they are interconnected by the belt speed and can be set equal to each other.
3450 rpm * ((PI)*1.5") = unknown rpm * ((PI)*2.5")
(3450 * 4.712)/7854 = Unknown rpm = 2070 rpm
So this speed reduction means your 6" buffer is spinning at 2070 rpm since it spins at the same rate as your pulley.
However, if you want to know the rate that the outside edge is going by your razor, you will utilize part of the process we did above again.
2070 rpm * ((PI)*6")= 2070 rpm * 18.85 in =
39,019 inches per minute which if you divide by 60 to get it into the form of per second gives 39,019 / 60 = 650 inches per second.
So the rate that the polishing wheel edge passes the razor blade will be 650 inches per second.
Hope this helps and that I did not confuse or bore you too much.
A site that gives a visual of the first part is Determining Pulley Speeds
Hey Paco! One of MUrphy's rules of combat states,"If it is stupid but it works, it aint stupid!". Well done my friend, thanks for the pic.
650 inches per sec / 12 = 54 feet per second x 60 = 3250 surface feet per minute . That is fast!
Lets try a shorthand calc
Simply, if the motor shaft pulley is 3" and the buffing wheel shaft pulley is 6" then the speed is reduced by 1/2.
3" divided by 6" = 2...so divide the rpm by 2 to get the rpm of the buffing wheel drive shaft 3450 / 2 = 1725 rpm
in your case
1.5" / 2.5" = 0.6
0.6 ( or 60 %) X 3450 = 2070 rpm on the buffing wheel drive shaft
To calculate the surface feet per minute of the buffing wheel
6" x Pi ( 3.146) = 18.876 ", the circumference of the buffing wheel
18.876 x 2070 rpm ( which is the rate the buffing wheel is turning)
18.876 x 2070 = 39073 surface inches per minute divided by 12 inches per foot = 3256 sfpm ( surface feet per minute)
===========================================
So, if you want to reduce your speed by 1/2 get a pulley twice as big. If you want to reduce your speed to 1/4 then get a pulley 4 times bigger, etc.
Hope this helps,;)
Thanks Noswad, and Randy, I remember discussing this at the meetup.
