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Thread: My bevel angle calculations

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    yeehaw. Ben325e's Avatar
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    Quote Originally Posted by StraightRazorDave View Post
    Ah, I like it. Thanks. I didn't measure the width of the blade directly, but used a diagonal measurement from the bevel to the edge of the spine. I figured this would be easier to measure physically then the actualy width, since you would need to measure the cross-section essentially, which would be impossible if you were measuring the bevel angle in the middle on the blade. Does that make sense? In my diagram, the actual width of the razor is z, but if you actually measure your razor it would be easier to measure y, the hypotenuse.

    I like your idea of using an integral multiple of the number of tape layers. I just figured you could just substitute the total thickness in for t, but your way is more eligant.
    I can get on board with that - the measurement would be easier. So:

    Let:

    x = spine width
    y= distance from spine/hone contact point to tip of bevel
    n = number of tape layers
    t = thickness of tape
    Θ = total bevel angle °


    total bevel angle:

    Θ = 2{arcsin[(.5x + nt)/y]}

  2. The Following User Says Thank You to Ben325e For This Useful Post:

    StraightRazorDave (07-08-2009)

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