Thread: bevel width

Hi,
What widths of cutting edge would be proper for full wedge, 1/4 hollow, 1/2 hollow, full hollow razors? Let's say blade widths are a, b, c, d. I believe it's non-linearly proportional to blade width but cannot formulate it so maybe I'm wrong.

Edit 1:
I'm assuming blade thickness varies with width so as to keep the bevel angle constant.

Let me put a crude classification here:

Hollowness:
full wedge:A
1/4 hollow:B
1/2 hollow:C
full hollow: D

blade width:
15 mm(or 5/8) = a
18 mm (or 6/8)= b
20 mm (or 7/8) =c
25 mm (8/8) = d

So what edge width should a "A-b" razor have? What about others?

Edit 2:
This makes 4x4=16 razors. Pick any combination you are familiar with and tell which bevel width you prefer, that will also help.

Thanks.

Originally Posted by ferroburak

Hi,
What widths of cutting edge would be proper for full wedge, 1/4 hollow, 1/2 hollow, full hollow razors? Let's say blade widths are a, b, c, d. I believe it's non-linearly proportional to blade width but cannot formulate it so maybe I'm wrong.
Thanks.

I may misunderstand your question .
cutting edge has nothing to do with grind of the blade?

I'm sorry, I don't think I quite understand what you are asking here.

Are you talking about bevel widths in relation to grind and blade widths?

If so, then the more hollow the blade is, the narrower the bevel ,and the more wedge-like it is, the wider it becomes. Given the same spine-size. A full wedge has the whole blade side as a bevel.
Then the blade widths works the other way, given the spine is of a constant size.
The wider the spine is, the narrower the bevel becomes. Naturally not so on the true wedge.

Or something to that effect

Originally Posted by hi_bud_gl

I may misunderstand your question .
cutting edge has nothing to do with grind of the blade?

I think they counter act(not sure this is the correct word). The more hollow the blade narrower the edge width should be so that bevel flexes in desired amounts during use.

Originally Posted by Birnando

I'm sorry, I don't think I quite understand what you are asking here.

Are you talking about bevel widths in relation to grind and blade widths?

If so, then the more hollow the blade is, the narrower the bevel ,and the more wedge-like it is, the wider it becomes. Given the same spine-size. A full wedge has the whole blade side as a bevel.



Then the blade widths works the other way, given the spine is of a constant size.
The wider the spine is, the narrower the bevel becomes. Naturally not so on the true wedge.

Or something to that effect

I agree with the first part but couldn't understand the second part.

there is differences between bevel and edge.
Edge is cutting edge which cuts the hairs.
Bevel has nothing to do with cutting .
i hope i was clear.

Ok let me put a crude classification here:

Hollowness:
full wedge:A
1/4 hollow:B
1/2 hollow:C
full hollow: D

blade width:
15 mm(or 5/8) = a
18 mm (or 6/8)= b
20 mm (or 7/8) =c
25 mm (8/8) = d

So what edge width should a "A-b" razor have? What about others?

Originally Posted by ferroburak

I agree with the first part but couldn't understand the second part.

What I mean is, given a constant spine width, the bigger the blade is, the wider the bevel becomes. Bigger blades in this context meaning wider. E.g. a 4/8 vs 8/8, the bevel on the 8/8 will be wider than the one on the 4/8, if the spine width and grind is constant.

Originally Posted by ferroburak

I think they counter act(not sure this is the correct word). The more hollow the blade narrower the edge

Sorry it is not.

width should be so that bevel flexes in desired amounts during use.

Are you trying to ask width of the bevel? or the blade?

Originally Posted by hi_bud_gl

Sorry it is not.

Are you trying to ask width of the bevel? or the blade?

Hi,
I mean bevel, I don't think bevel width can be chosen arbitrarily so my question came from it.