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Of course :)

Again for a 7/8"

7 ÷ 8=0.875
0.875 ÷ 3.5 =0.25
0.25=1/4"

Or 4 instead of 3.5 if you want a slightly steeper bevel.

Equilateral triangle is what you mean.

OK, where did you get 60 from?

My point was for any given blade height you wanted to make, find the width needed for the correct honing angle.

Here the example doesn't match our blade geometry but imagine an isosceles triangle with c? being the short side (spine) and gamma (205809) our bevel angle.

205806

Two sides and the included...