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And of course, as you point out, the actual height of the BEVEL will determine the width can use a piece of stock, even one that might normally be a tad too "thin" if you measured all the way from...

You lost me as my only extensive exposure radians was milliradians when trying to get a rough idea of where an artillery shell might fall and even then, we couldn't say the entire word. Just mils....

With the Isosceles triangle as you starting point, all three angles are 60 degrees, Divide by the long ratio. 60 divided by 4 equals 15. Not exact science as the angle of each side would actually be...

Or in the case of a 1 to 4 thickness to height ratio you can just divide 60 by 4 and get 15. That's math for the liberal arts major. :p

Thanks, Bruno I just did the basic math in my head for the first time. So does that mean twin you guys are talking about a 15 to 16 degree bevel angle, that is the TOTAL included angle?:dropjaw:

In some ways this seems kind of obvious, but as a newbie, i can't fall into that trap. From what I have gathered from the very helpful folks on this forum, the ratio of width of the blade should be...