
Originally Posted by
2knives
I would say 9 out of 10 of the razor I have come across have a pivot hole in the tang of the blade that is larger than 1/16".
Let's hash this out. Let's say you have circular hole (pivot hole in tang) that has a 1/8" diameter and you put a 1/16" rod into the hole. Now take the area of the hole A=PI(r)^2 -> PI(1/8)^2 = 0.04908" = A1. Now take the orthogonal cross sectional area of the rod PI(1/16)^2 = 0.0123" = A2. So A1-A2 = 0.04908 - 0.0123 = 0.03678... seems like a lot of area left over; but, we must remember that it is a circle... so, When dealing with a circle, the you have a radius and a diameter. The radius of the 1/8" hole is 1/16". The radius of the 1/16" rod is 1/32". So 1/16 = 0.0625 = r1 & 1/32 = 0.03125 = r2 and if you subract r1-r2 = 0.0625-0.03125 = 0.03125 which equals 1/32. If you are lost right now, because it certainly is confusing, what this math indicates is that you are looking at a 1/32" gap from pivot pin to tang hole when the rod is centered... pretty small.
In conclusion, if the razor is pinned right and tight (not too tight though), I don't think you'll have much of a problem with the hole in the tang being 1/8" and the rod being 1/16". If you're a perfectionist then you might want to fill the hole in the tang... If you'd rather spend your time doing something else, then I think you'll be juuuuust fine.
Cheers!
-2knives