Thread: Latest custom builds

I say 14 degrees 56 minutes

Hmmmmmmm...................

But then again I did go thru the Philadelphia public school system.
Here's my diploma see It hardly looks like my handwriting.
Har!!!!

I got 15.43 degrees or so. Thats rounded obviously.


Am I right???

Originally Posted by Tarkus

I say 14 degrees 56 minutes

Originally Posted by ncraigtrn

I got 15.43 degrees or so. Thats rounded obviously.


Am I right???

Looks as you guys are right close together! I never did Trig, a bit of geometry. Have no idea!
At least you 2 are versed enough to eliminate all the useless measurements I gave!
This begs the question.....Is a 14.5 degree angle good for shaving?
Was thinking of lopping off this blade and making a Kamimicrotome razor!

Originally Posted by ncraigtrn

I got 15.43 degrees or so. Thats rounded obviously.


Am I right???

nope. its roughly 30 degrees effective cutting angle. good grief, thats about what my axes are, for some reason I pictured microtomes being a more acute angle than that.
I might be wrong on that angle, I don't know formulas too well so I had to go oldschool. now the bigger question is this: what is the actual width of the "spine" created using that frameback? the diameter of the frame is 16mm but the points where it contacts the hone are not across the diameter of the frame but slightly down from the "equator." so the measure between those points would be the spine width...... what is it?
ps- using the 16mm width will give the wrong angle as an answer for the effective cutting angle. to solve for cutting angle you NEED to know the width between those points where the frame contacts the hone......

Originally Posted by silverloaf

nope. its roughly 30 degrees effective cutting angle. good grief, thats about what my axes are, for some reason I pictured microtomes being a more acute angle than that.
I might be wrong on that angle, I don't know formulas too well so I had to go oldschool. now the bigger question is this: what is the actual width of the "spine" created using that frameback? the diameter of the frame is 16mm but the points where it contacts the hone are not across the diameter of the frame but slightly down from the "equator." so the measure between those points would be the spine width...... what is it?

30 mm x 16mm. Distance where the frameback spine hits the hone and to the edge diameter of the frameback at the point of contacting the hone! Seems you have not divided by 2 somewhere! Lord knows! I certainly don't!

30mm from the point of spine on hone to cutting edge. diameter of frame is 16mm, radius of 8mm. a right triangle using the 30mm and 8mm still only gives you half the effective cutting angle. so the effective angle is roughly 30 unless im really missing something. you wouldn't divide by 2 to get effective angle. im gonna feel incredibly stupid if im this wrong after drawing out the stinkin thing! hahaha

I dunno. Seems some table comes into play. Simpletons like us cannot comprehend!
My fine friend Tarkus wil explain! Tomorrow!

Originally Posted by sharptonn

30 mm x 16mm. Distance where the frameback spine hits the hone and to the edge diameter of the frameback at the point of contacting the hone! Seems you have not divided by 2 somewhere! Lord knows! I certainly don't!

I aint seein' it man, I may have to rescind my "nope!" im reading it as the frame is tubular and has a diameter of 16mm. is it 16mm across the point where it hits the hone? then im reading that the height fro cutting edge to where the frame hits hone is 30mm. I don't think im confused anywhere so far???? so if I made a right triangle with 30mm being the long side and 8mm being the short then my cutting angle is 14.9ish. I would double that to get my effective cutting angle since that gives me only one side of my blade??????????