Results 1 to 10 of 16

Hybrid View

randydance062449 Computing the angle... 12-12-2005, 04:51 AM
aschaab Hi Randy, ad 1): its basic... 12-12-2005, 06:25 AM
randydance062449 Thanks guy!:) Now, to get... 12-12-2005, 05:55 PM
Joe Lerch This is not correct. The... 12-14-2005, 04:39 AM
aschaab Hi Joe, yes, I stand... 12-14-2005, 06:03 AM
dawill use the windows OS calc... 12-12-2005, 06:15 PM
randydance062449 Thanks guys!:) I now have... 12-13-2005, 02:21 AM
xman :thinking: must be voodoo 'r... 12-13-2005, 02:44 AM
440stainless I think theres a slight... 12-13-2005, 03:06 AM
randydance062449 Thanks for the reply.:) I... 12-13-2005, 04:06 AM
superfly Randy, just hone the dam... 12-13-2005, 10:07 AM
Joe Lerch The error in the answer is... 12-14-2005, 04:56 AM
Joe Lerch You don't know the... 12-14-2005, 04:53 AM
  1. #1
    Senior Member dawill's Avatar
    Join Date
    Nov 2005
    Location
    Brea, CA
    Posts
    114
    Thanked: 0

    Default

    use the windows OS calc applet and change to scientific functions.

    Start > Run > "calc" > View > Scientific

    That should get your all the geometric functions you need.

  2. #2
    Hones & Honing randydance062449's Avatar
    Join Date
    May 2005
    Location
    Saint Paul, Minnesota, United States
    Posts
    8,023
    Thanked: 2209
    Blog Entries
    1

    Default

    Thanks guys!

    I now have what I was looking for, either a formula or a constant for asin and sin. Now I have them

    asin= 57.68479516........
    sin= .017391304..........

    so

    angle of blade= asin(thickness of spine/ width of blade)
    57.68479516(1/8 divided by 5/8)
    57.68479516(.125/.625)
    57.68479516(.2)= 11.5......

    To compute the desired thickness of the spine at a specific spot on the blade so that the angle of the blade is constant when the width of the blade is not constant the formula is

    Desired spine thickness at point2 =sin(angle of blade at point 1)*(blade width at point 2.)

    .017391304(11.5)*0.5= 0.0999999 or .1 or 1/10th of an inch.

    Thanks Axel!
    Randolph Tuttle, a SRP Mentor for residents of Minnesota & western Wisconsin

  3. #3
    Super Shaver xman's Avatar
    Join Date
    May 2005
    Location
    Lotus Land, eh
    Posts
    8,194
    Thanked: 622

    Question

    must be voodoo 'r some devil speak maybe.

  4. #4
    Junior Member
    Join Date
    Nov 2005
    Posts
    23
    Thanked: 0

    Default

    I think theres a slight problem with the algebra there. Trigonometric functions work only for right triangles. The only right triangle you can really make there is by laying the blade on a flat surface. The hypotenuse of the right triangle is the line from the very edge of the blade to the middle of the spine (when looking at it end-on) and tue only leg of the triangle that you can measure is the line from the tip of the blade to the point at which the spine touches the hone.

    The two lengths you know form the angle you want to find out (or rather half of the angle). So you use the inverse cosine function: acos(leg/hypotenuse) and multiply that angle by two to get the full angle of the blade. If you want a formula for the width of the spine at a given point on the blade, you can extrapolate a linear function for the width of the blade at a given point and use it to create a function that gives the width of the spine.

  5. #5
    Hones & Honing randydance062449's Avatar
    Join Date
    May 2005
    Location
    Saint Paul, Minnesota, United States
    Posts
    8,023
    Thanked: 2209
    Blog Entries
    1

    Default

    Thanks for the reply.

    I would venture a guess that the previous example's answer of 11.5 degrees
    is close to the full "included" angle and that if we divide that by 2 we will be close to the actual angle. But thats only a guess on my part. I will look and see what is posted on the other forums. This should be interesting.

    Quote Originally Posted by 440stainless
    I think theres a slight problem with the algebra there. Trigonometric functions work only for right triangles. The only right triangle you can really make there is by laying the blade on a flat surface. The hypotenuse of the right triangle is the line from the very edge of the blade to the middle of the spine (when looking at it end-on) and tue only leg of the triangle that you can measure is the line from the tip of the blade to the point at which the spine touches the hone.

    The two lengths you know form the angle you want to find out (or rather half of the angle). So you use the inverse cosine function: acos(leg/hypotenuse) and multiply that angle by two to get the full angle of the blade. If you want a formula for the width of the spine at a given point on the blade, you can extrapolate a linear function for the width of the blade at a given point and use it to create a function that gives the width of the spine.
    Randolph Tuttle, a SRP Mentor for residents of Minnesota & western Wisconsin

  6. #6
    Senior Member superfly's Avatar
    Join Date
    May 2005
    Location
    Toronto, ON
    Posts
    1,950
    Thanked: 16

    Default

    Randy, just hone the dam razor...

  7. #7
    Junior Member
    Join Date
    Nov 2005
    Posts
    23
    Thanked: 0

    Default

    Hehe. He may have a point Randy. When you're doing any sort of weird inverse trigonometric function to get an angle, the answer you get is only as exact as the measurements you take. In the case of this razor (and razors in general) you're dealing with fairly small distances which you might have better luck measuring with calipers or something and it feels like one would mess up the edge with one of those. You can probably just do it by feel and it'll turn out fine.

  8. #8
    Senior Member Joe Lerch's Avatar
    Join Date
    May 2005
    Location
    New Jersey
    Posts
    1,331
    Thanked: 8

    Default

    Quote Originally Posted by randydance062449
    Thanks for the reply.

    I would venture a guess that the previous example's answer of 11.5 degrees
    is close to the full "included" angle and that if we divide that by 2 we will be close to the actual angle. But thats only a guess on my part. I will look and see what is posted on the other forums. This should be interesting.
    The error in the answer is small because it's a small angle, but the formula is wrong.

  9. #9
    Senior Member Joe Lerch's Avatar
    Join Date
    May 2005
    Location
    New Jersey
    Posts
    1,331
    Thanked: 8

    Default

    Quote Originally Posted by 440stainless
    I think theres a slight problem with the algebra there. Trigonometric functions work only for right triangles. The only right triangle you can really make there is by laying the blade on a flat surface. The hypotenuse of the right triangle is the line from the very edge of the blade to the middle of the spine (when looking at it end-on) and tue only leg of the triangle that you can measure is the line from the tip of the blade to the point at which the spine touches the hone.

    The two lengths you know form the angle you want to find out (or rather half of the angle). So you use the inverse cosine function: acos(leg/hypotenuse) and multiply that angle by two to get the full angle of the blade. If you want a formula for the width of the spine at a given point on the blade, you can extrapolate a linear function for the width of the blade at a given point and use it to create a function that gives the width of the spine.
    You don't know the hypotenuse. You only know the opposite side (half the spine) and the adjacent side (the width of the blade). So, you're really dealing with a tangent.

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •