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Thread: Computing the angle...
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12-12-2005, 06:15 PM #1
use the windows OS calc applet and change to scientific functions.
Start > Run > "calc" > View > Scientific
That should get your all the geometric functions you need.
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12-13-2005, 02:21 AM #2
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Thanked: 2209Thanks guys!
I now have what I was looking for, either a formula or a constant for asin and sin. Now I have them
asin= 57.68479516........
sin= .017391304..........
so
angle of blade= asin(thickness of spine/ width of blade)
57.68479516(1/8 divided by 5/8)
57.68479516(.125/.625)
57.68479516(.2)= 11.5......
To compute the desired thickness of the spine at a specific spot on the blade so that the angle of the blade is constant when the width of the blade is not constant the formula is
Desired spine thickness at point2 =sin(angle of blade at point 1)*(blade width at point 2.)
.017391304(11.5)*0.5= 0.0999999 or .1 or 1/10th of an inch.
Thanks Axel!Randolph Tuttle, a SRP Mentor for residents of Minnesota & western Wisconsin
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12-13-2005, 02:44 AM #3
must be voodoo 'r some devil speak maybe.
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12-13-2005, 03:06 AM #4
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Thanked: 0I think theres a slight problem with the algebra there. Trigonometric functions work only for right triangles. The only right triangle you can really make there is by laying the blade on a flat surface. The hypotenuse of the right triangle is the line from the very edge of the blade to the middle of the spine (when looking at it end-on) and tue only leg of the triangle that you can measure is the line from the tip of the blade to the point at which the spine touches the hone.
The two lengths you know form the angle you want to find out (or rather half of the angle). So you use the inverse cosine function: acos(leg/hypotenuse) and multiply that angle by two to get the full angle of the blade. If you want a formula for the width of the spine at a given point on the blade, you can extrapolate a linear function for the width of the blade at a given point and use it to create a function that gives the width of the spine.
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12-13-2005, 04:06 AM #5
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Thanked: 2209Thanks for the reply.
I would venture a guess that the previous example's answer of 11.5 degrees
is close to the full "included" angle and that if we divide that by 2 we will be close to the actual angle. But thats only a guess on my part. I will look and see what is posted on the other forums. This should be interesting.
Originally Posted by 440stainless
Randolph Tuttle, a SRP Mentor for residents of Minnesota & western Wisconsin
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12-13-2005, 10:07 AM #6
Randy, just hone the dam razor...
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12-13-2005, 11:34 AM #7
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Thanked: 0Hehe. He may have a point Randy. When you're doing any sort of weird inverse trigonometric function to get an angle, the answer you get is only as exact as the measurements you take. In the case of this razor (and razors in general) you're dealing with fairly small distances which you might have better luck measuring with calipers or something and it feels like one would mess up the edge with one of those. You can probably just do it by feel and it'll turn out fine.
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12-14-2005, 04:56 AM #8
Originally Posted by randydance062449
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12-14-2005, 04:53 AM #9
Originally Posted by 440stainless